A ball hits a wall horizontly at 6 m/s. It rebounds horizontly at 4.4m/s.The ball is in contact with the wall for .04 sec. What is the acceleration of the ball?

Asked by gspublicschool | 11th Dec, 2019, 08:33: AM

Expert Answer:

initial velocity, u = 6 m/s and final velocity, v= -4.4 m/s
time = 0.04s
thus acceleration = (v-u)/t
a =(- 4.4 - 6)/ 0.04  = -10.4/ 0.04  = -260 m/s2 
 
Note: v is taken as negative because it's in opposite direction as that of initial velocity. 

Answered by Shiwani Sawant | 11th Dec, 2019, 12:43: PM