A ball falls vertically downward and bounces off a horizontal floor. The speed of the ball just before reaching the floor (u1) is equal to the speed just after leaving contact with the floor (u2); u1=u2. The corresponding magnitudes of accelerations are denoted respectively by a1 and a2. The air resistance during motion is proportional to speed and is not negligible. If g is acceleration due to gravity then how are the two accelerations related?

Asked by  | 11th Nov, 2012, 12:11: AM

Expert Answer:

Let before reaching the ground,
mg – F – ma1

a1 = g –(F/m)
And after bouncing,
mg + F = ma2
a2 = g + (F/m)
a2 > a1

Answered by  | 12th Nov, 2012, 12:04: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.