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ICSE Class 10 Answered

a, b, c are in continued  proportion , prove that  a\c =   2a2−5ab+7b2\2b2−5bc+ 7c2
Asked by tafeelsayyed786 | 19 Sep, 2020, 01:56: PM
answered-by-expert Expert Answer
Given: a, b and c are in continued proportion
straight a over straight b equals straight b over straight c rightwards double arrow straight b squared equals ac Consider comma fraction numerator 2 straight a squared minus 5 ab plus 7 straight b squared over denominator 2 straight b squared minus 5 bc plus 7 straight c squared end fraction equals fraction numerator 2 straight a squared minus 5 ab plus 7 ac over denominator 2 ac minus 5 bc plus 7 straight c squared end fraction equals fraction numerator straight a open parentheses 2 straight a minus 5 straight b plus 7 straight c close parentheses over denominator straight c open parentheses 2 straight a minus 5 straight b plus 7 straight c close parentheses end fraction equals straight a over straight c Hence comma space straight a over straight c equals fraction numerator 2 straight a squared minus 5 ab plus 7 straight b squared over denominator 2 straight b squared minus 5 bc plus 7 straight c squared end fraction
Answered by Renu Varma | 22 Sep, 2020, 02:11: PM

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