[a-b. 2a+c]=[-1 5].  [2a-b. 3c+2]=[0 13]. Find the a b c and d

Asked by madankumar47 | 2nd Jun, 2020, 12:49: PM

Expert Answer:

The question you have asked is:
If [a-b, 2a+c  //  2a-b, 3c+d] = [-1, 5 // 0, 13] find the values of a, b, c and d.
open square brackets table row cell straight a minus straight b end cell cell 2 straight a plus straight c end cell row cell 2 straight a minus straight b end cell cell 3 straight c plus straight d end cell end table close square brackets equals open square brackets table row cell negative 1 end cell 5 row 0 13 end table close square brackets
If space two space matrices space are space equal space then space their space corresponding space elements space are space equal.
Therefore comma space we space have
straight a minus straight b equals negative 1 space... space left parenthesis 1 right parenthesis
2 straight a plus straight c equals 5 space space space... space left parenthesis 2 right parenthesis
2 straight a minus straight b equals 0 space space space... space left parenthesis 3 right parenthesis
3 straight c plus straight d equals 13 space space... space left parenthesis 4 right parenthesis
Solving space left parenthesis 1 right parenthesis space and space left parenthesis 3 right parenthesis space simultaneously space we space get
straight a equals 1 space and space straight b equals 2
Substituting space straight a space in space left parenthesis 2 right parenthesis comma space we space get
2 plus straight c equals 5 space space rightwards double arrow space straight c equals 3
Substituting space straight c space in space left parenthesis 4 right parenthesis comma space we space get
9 plus straight d equals 13 space space rightwards double arrow space straight d equals 4

Answered by Renu Varma | 2nd Jun, 2020, 01:12: PM