(a) Apply Kirchoff's loop rule to loop 1. Write down the equation; from your equation, solve for.I1.
(b) Apply Kirchoff's loop rule to loop 2. Write down the equation and solve for I2.
(c) How much power is the 5 V battery putting into the circuit?

Asked by Topperlearning User | 27th Apr, 2015, 02:54: PM

Expert Answer:

(a) Note that I3 = 0.500 A.
Starting in the bottom left corner and going around the loop clockwise gives:
Solving for I1 gives:
 
(b) Starting in the bottom right corner and going around the loop counter-clockwise gives:
Solving for I2 gives:
 
(c) For a battery the simplest thing to do is to apply P = VI. For this battery the current is 0.2 A, so the power is P = 5 (0.2) = 1 W.

Answered by  | 27th Apr, 2015, 04:54: PM