A and B are two sources generating sound waves.a listener is situated at c.the frequency of source A is 500 hz. A , now moves with a velocity of 4m/s towards c .the number of beats heard at c is 6.when A moves away from c at a speed of 4m/s , the number of beats heard at c is 18.the speed of sound is 340m/s.the frequency of source at b is what??

Asked by prabhakar p | 14th May, 2013, 07:05: AM

Expert Answer:

let the frequence of source at B = v
frequence of source A heard at C when it is coming close to C is = 340/(340-4) * 500 = 506 Hz
thus beats produced, 6 = 506-v
frequency of source A heard at C, when it is receeding from C = 340/(340+4) *500 = 494 Hz
thus beats produced in this case, 18 = v - 494
solving we can get the frequency of the source B

Answered by  | 28th May, 2013, 11:03: PM

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