A and B are ideal gases . The molecular weights of A and B are in the ratio of 1:4.The pressure of a gas mixture containing equal weights of A and B is p atm . What is the partial pressure (in atm ) of B in the mixture.
Asked by Balbir | 21st Jul, 2019, 01:39: PM
Molecular weights of gases A and B are in the ratio of 1:4.
Molecular weight of gas A = 'x'
Molecular weight of gas B = '4x'
The mixture gases conatins equal weights of gas A and gas B
Weight of gas A = Weight of gas B = 'm' gm
Let total pressure be 'P'
To calculate the partial pressure of gas B in the mixture, lets first calculate the mole fraction of gas B.
Mole fraction of gas B
Answered by Varsha | 21st Jul, 2019, 11:22: PM
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