A 8000 KG ENGINE PULLS A TRAIN OF 5 WAGAONS EACH OF 2000 KG ALONG A HORIZONTAL TRACK . IF THE ENGINE

Asked by  | 19th Jul, 2008, 10:43: PM

Expert Answer:

Net accelerating force,F=Force due to engine- Frictional force=40000-5000=35000 N

The acceleration of train,a=F/M=35000/18000=35/18=1.87 ms-2

 

friction force on the four wagons=8000/18000 * 5000=20000/9 N

Let the required force be F'.

F'-20000/9=(800)(35/18)

or F'=        (14000+20000)/9=34000/9=3777.77 N

 

 

Answered by  | 23rd Jul, 2008, 03:04: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.