A 2cm tall object at a distance of 15cm is placed perpendicular to the principal axis of a lens of focal length 10cm. If it forms an image of double of its size, find the possible positions of image?

Asked by  | 5th Mar, 2013, 06:16: PM

Expert Answer:

m= magnification=2=v/u    v=2u     now put in lens formula and solve:
v=2x(-15)=-30 cm
size of image:
I/O=2
I=4cm

Answered by  | 6th Mar, 2013, 04:52: PM

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