A 20 gram bullet moving with 200 m/s stops after penetrating a 2 cm of bone. Calculate the average force exerted by the bullet.
Asked by Topperlearning User | 4th Jun, 2014, 08:27: AM
Here we are given,
Mass of the bullet = 20 g = 20 × 10-3 kg
Initial velocity of the bullet is u = 200 m/s
Distance traveled = 2 cm = 2 × 10-2 m
Using 3rd equation of motion, we get
From Newton's second law, we have
Answered by | 4th Jun, 2014, 10:27: AM
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