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a^2+b^2+c^2=2(a-b-c)-3 Find a^2+b^2-c  (Answer lies between 0 and 9 , both inclusive)
Asked by raunak.kumar | 15 Feb, 2021, 02:37: PM Expert Answer
a2 + b2 + c2 = 2(a - b - c) - 3
a2 - 2a + 1 + b2 + 2b + 1 + c2 + 2c + 1 = 0
(a - 1)2 + (b + 1)2 + (c + 1)2 = 0
As square is always greater then or equal to 0, we have
a - 1 = 0, b + 1 = 0 and c + 1 = 0
a = 1, b = -1 and c = -1
Answered by Renu Varma | 17 Feb, 2021, 10:56: AM
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