A 100 g block is connected to a horizontal massless spring of force constant 25.6 N/m .The block is free to oscillate on a horizontal frictionless surface .The block is displaced 3 cm from the equilibrium position and at t=0 ,it is released from rest at x=0.It executes SHM with the (+)ve x-direction. Find the Position time equation of the SHM Of block.
Asked by vaibhav gupta
| 30th Jun, 2013,
03:17: PM
Expert Answer:
m = 100g = 0.1kg
k = 25.6N/m
Amplitude (A) = 3cm = 0.03 m

Answered by
| 30th Jun, 2013,
04:51: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change