A 100 g block is connected to a horizontal massless spring of force constant 25.6 N/m .The block is free to oscillate on a horizontal frictionless surface .The block is displaced 3 cm from the equilibrium position and at t=0 ,it is released from rest at x=0.It executes SHM with the (+)ve x-direction. Find the Position time equation of the SHM Of block.

Asked by vaibhav gupta | 30th Jun, 2013, 03:17: PM

Expert Answer:

m = 100g = 0.1kg
k = 25.6N/m 
 
Amplitude (A) = 3cm = 0.03 m 
 
 

Answered by  | 30th Jun, 2013, 04:51: PM

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