A^1/x=b^1/y=c^1/z and abc =1 find the value of x+y+z

Asked by Shringoyal | 1st May, 2015, 04:55: PM

Expert Answer:

Let

$a to the power of 1 divided by x end exponent equals b to the power of 1 divided by y end exponent equals c to the power of 1 divided by z end exponent equals K rightwards double arrow a equals K to the power of x comma space b equals K to the power of y comma space c equals K to the power of z rightwards double arrow a b c equals K to the power of x cross times K to the power of y cross times K to the power of z equals K to the power of open parentheses x plus y plus z close parentheses end exponent$

Given that, abc=1

$rightwards double arrow K to the power of left parenthesis x plus y plus z right parenthesis end exponent equals 1 rightwards double arrow x plus y plus z equals 0$

Answered by satyajit samal | 2nd May, 2015, 02:24: PM

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