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9th numerical Asked by lovemaan5500 | 07 Dec, 2019, 08:51: PM Expert Answer
Equation given below gives the relation between object and image distance in terms of refractive index of the medium
and the radius of curvature of the curved spherical surface.

(n2/v) - (n1/u) = ( n2 - n1)/R  .....................(1)

where n2 is the refractive index of medium where image is formed, v is the imge-to-spherical surface distance,
n1 is the refractive index of of medium where light ray incident on spherical surface and R is radius of curvature of spherical surface.

Using the  eqn.(1), we have,   (1/v) + (1.5/12) = (1-1.5)/(-2)  ...................(2)

In the above eqn.(2), cartesian sign convention is followed, hence u is negative and radius of curvature is negative.

Hence from eqn.(2), we get, (1/v) = (1/4) - (1/8) = 1/8   or v = 8 cm

image is formed right side of spherical surface at a distance 8 cm
Answered by Thiyagarajan K | 07 Dec, 2019, 10:59: PM

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