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CBSE Class 12-science Answered

8th ques
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Asked by lovemaan5500 | 22 Feb, 2020, 10:16: PM
answered-by-expert Expert Answer
Magnetic field at centre of coil = ( μo n i ) / (2 R )
 
where n is number of turns, i is current in the coil and R is radius of coil
 
if coil diameter d is 16 cm  and coil is made from wire of length 40 m ,
then number of turns n = 40 / (πd ) = 40 / (π×0.16 ) ≈ 79 turns
 
Hence magnetic field B = ( 4π × 10-7 × 79 × 5 ) /( 2 × .08 ) = 3.1 × 10-3 T
Answered by Thiyagarajan K | 23 Feb, 2020, 09:15: AM

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CBSE 12-science - Physics
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