8th ques

Asked by lovemaan5500 | 22nd Feb, 2020, 10:16: PM

Expert Answer:

Magnetic field at centre of coil = ( μo n i ) / (2 R )
 
where n is number of turns, i is current in the coil and R is radius of coil
 
if coil diameter d is 16 cm  and coil is made from wire of length 40 m ,
then number of turns n = 40 / (πd ) = 40 / (π×0.16 ) ≈ 79 turns
 
Hence magnetic field B = ( 4π × 10-7 × 79 × 5 ) /( 2 × .08 ) = 3.1 × 10-3 T

Answered by Thiyagarajan K | 23rd Feb, 2020, 09:15: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.