# ICSE Class 9 Answered

**8a³ - 2b³**

Asked by Swatisasturkar | 04 Feb, 2023, 01:38: PM

Expert Answer

8 a

^{3}- 2 b^{3}= (2a)

^{3}- ( p b )^{3}, where p == ( 2a - p ) [ (2a)

^{2}- 3 (2a) (pb) (2a - pb ) + p^{2}]= ( 2a - p ) [ 4 a

^{2}- 6 a p ( 2a - p ) + p^{2}]= ( 2a - p ) [ 4 a

^{2}- 12 a^{2}p b + 6 a p^{2}b^{2}+ p^{2}]- - - - - - - - - - - - - - - - - - - - -

Answered by Thiyagarajan K | 04 Feb, 2023, 02:55: PM

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