ICSE Class 9 Answered
8a³ - 2b³
Asked by Swatisasturkar | 04 Feb, 2023, 01:38: PM
Expert Answer
8 a3 - 2 b3
= (2a)3 - ( p b )3 , where p = 
= ( 2a - p ) [ (2a)2 - 3 (2a) (pb) (2a - pb ) + p2 ]
= ( 2a - p ) [ 4 a2 - 6 a p ( 2a - p ) + p2 ]
= ( 2a - p ) [ 4 a2 - 12 a2p b + 6 a p2 b2 + p2 ]
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Answered by Thiyagarajan K | 04 Feb, 2023, 02:55: PM
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