CBSE Class 11-science Answered
7. 12 + (12 + 22) + (12 + 22 + 32) + ...
Asked by | 11 Oct, 2008, 12:23: PM
Expert Answer
7. 12 + (12 + 22) + (12 + 22 + 32) + ... = [7. 12 ]+ (12 + 22) + (12 + 22 + 32) + ...
The firsr term is = 84. Now look at the terms starting from the second (12 + 22) + (12 + 22 + 32) + ...
The general term will be sum of AP with a = 12 and d = 10. i,e n/ 2 [ 2 x 12 + ( n-1) 10] = 7n + 5 n2
7n + 5 n2 = is the sum of the given series from second term onwards . I presume it is till (n+1) the terms
so 7 n (n+1) / 2 + 5n (n+1) (2n +1) / 6 = n(n+1) / 2 [ 7 + 5(2n +1) /3 ]
=n(n+1) / 2[26+10n] / 6
So 7. 12 + (12 + 22) + (12 + 22 + 32) + ... = 84 + n(n+1) [13+5n] / 6
Answered by | 12 Oct, 2008, 04:28: PM
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