6g of ethanol is present in 100g of water . find d mol fraction of each component .
Asked by shuchi.saumya
| 5th Aug, 2010,
12:00: AM
Expert Answer:
Molar mass of ethanol =12 X2 + 1 X 6 + 16
Molar mass of ethanol =46 g
Moles of ethanol= 6/46= 0.13 moles
Molar mass of water = 1 X2 +16 =18g
Moles of water= 100/18 = 5.5
Total number of moles = 5.5 + 0.13= 5.63
Mole fraction of ethanol = 0.13/5.63= 0.023
Mole fraction of water = 5.5/5.63 = 0.976
Molar mass of ethanol =46 g
Moles of ethanol= 6/46= 0.13 moles
Molar mass of water = 1 X2 +16 =18g
Moles of water= 100/18 = 5.5
Total number of moles = 5.5 + 0.13= 5.63
Mole fraction of ethanol = 0.13/5.63= 0.023
Mole fraction of water = 5.5/5.63 = 0.976
Answered by
| 6th Aug, 2010,
10:41: AM
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