ICSE Class 10 Answered
(6a+7b)(3c_4d)=(6c+7d)(3a_4b)
Asked by mama20brand04 | 19 May, 2020, 06:44: AM
Expert Answer
Given: a:b=c:d
To find: (6a+7b)(3c-4d)=(6c+7d)(3a-4b)
Let a:b=c:d=k
a=bk, c=dk
Consider,
LHS=(6a+7b)(3c-4d)=(6bk+7b)(3dk-4d)=bd(6k+7)(3k-4)
RHS=(6c+7d)(3a-4b)=(6dk+7d)(3bk-4b)=bd(6k+7)(3k-4)
Hence, (6a+7b)(3c-4d)=(6c+7d)(3a-4b)
Answered by Renu Varma | 21 May, 2020, 03:14: PM
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