6.4 kJ of energy causes a displacement of 64m in a body in the direction of force in 2.5s. calculate the force applied and the power in HP ( take i HP as 746 w)
Asked by mahimachaki chaki | 23rd Feb, 2014, 09:08: AM
Expert Answer:
According to work enegy theorm,
W = K.E = 6.4 kJ = 6.4 x 103 J
W = F.d. cos θ
Now the displacement of the body is in the direction of applied force.
θ = 0
W = F.d
F = W/d = (6.4 x 103 J)/64 m
F = 100 N
Power P = W/t
= (6.4 x 103 J)/(2.5)
=16 x 103 W
=1.6 x 104 W
= (1.6 x 104) / 746
= 0.0021 x 104 H.P.
Power P = 21 H.P.
W = F.d. cos θ
Now the displacement of the body is in the direction of applied force.
θ = 0
W = F.d
F = W/d = (6.4 x 103 J)/64 m
F = 100 N
Power P = W/t
= (6.4 x 103 J)/(2.5)
=16 x 103 W
=1.6 x 104 W
= (1.6 x 104) / 746
= 0.0021 x 104 H.P.
Power P = 21 H.P.
Answered by | 24th Feb, 2014, 03:15: PM
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