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Asked by fizzapanda | 6th Oct, 2020, 12:30: PM

Expert Answer:

TO solve the matrix equation [5 4 // 1 1] X = [1 -2 // 1 3]
Let space straight X equals open square brackets table row straight a straight b row straight c straight d end table close square brackets
As space open square brackets table row 5 4 row 1 1 end table close square brackets open square brackets table row straight a straight b row straight c straight d end table close square brackets equals open square brackets table row 1 cell negative 2 end cell row 1 3 end table close square brackets
rightwards double arrow space open square brackets table row cell 5 straight a plus 4 straight c end cell cell 5 straight b plus 4 straight d end cell row cell straight a plus straight c end cell cell straight b plus straight d end cell end table close square brackets equals open square brackets table row 1 cell negative 2 end cell row 1 3 end table close square brackets
rightwards double arrow space 5 straight a plus 4 straight c equals 1 space... space left parenthesis straight i right parenthesis
5 straight b plus 4 straight d equals negative 2 space... space left parenthesis ii right parenthesis
straight a plus straight c equals 1 space... space left parenthesis iii right parenthesis
straight b plus straight d equals 3 space... space left parenthesis iv right parenthesis
Solving space left parenthesis straight i right parenthesis space and space left parenthesis iii right parenthesis comma space we space get
straight a equals negative 3 space and space straight c equals 4
Solving space left parenthesis ii right parenthesis space and space left parenthesis iv right parenthesis comma space we space get
straight b equals negative 14 space and space straight d space equals space 17
Hence comma space straight X equals open square brackets table row cell negative 3 end cell cell negative 14 end cell row 4 17 end table close square brackets

Answered by Renu Varma | 7th Oct, 2020, 09:42: AM