CBSE Class 12-science Answered
5th ques
Asked by lovemaan5500 | 22 Feb, 2020, 10:16: PM
Expert Answer
Radius R of circular path of charged particle is given by,
R = ( m v ) / ( q B ) .................(1)
If kinetic energy E = (1/2)mv2 , then eqn.(1) is written in terms of kinetic energy as
R = ( 2 E m )1/2 / ( q B ) ............(2)
Hence radius R ( √m / q )
Let us take mass of proton as m, charge of proton as q and radius Rp .
Deutron mass is 2m and charge is q , hence radius RD = √2 Rp
Alpha particle mass is 4m and charge is 2q , hence Radius Rα = ( 4m )1/2 / (2q) = Rp
Hence , we get, Rp : RD : Rα = 1 : √2 : 1
Answered by Thiyagarajan K | 23 Feb, 2020, 10:25: AM
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