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CBSE Class 10 Answered

5.An observer 1.4 m tall is 10√3 away from a tower. The angle of elevation from his eye to the top of the tower is 60°. The heights of the tower is
Asked by mandalaganesh633 | 26 Nov, 2020, 05:55: PM
answered-by-expert Expert Answer
tan 60 to the power of o equals fraction numerator A B over denominator 10 square root of 3 end fraction
A B equals 30 m
Total height of the tower=30+1.4=31.4m
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