CBSE Class 11-science Answered
50ml of 0.10M HCL is mixed with 50ml of 0.10M NAOH.The solution of the temperature rises by 276K.Calculate the enthalpy of neutralization per mole of HCL.
1)-2.5*100 KJ
2)-1.3*100KJ
3)-8.4*10KJ
4)-6.3*10KJ
Asked by TVISHA Bhatt | 17 Aug, 2014, 03:32: PM
Expert Answer
The equation for the reaction is
1 mole of acid reacts with 1 mole of alkali to form 1 mole of water.
Number of moles of acid used = 0.05 x 0.1 = 0.005
Number of moles of alkali used = 0.05 x 0.1 = 0.005
So number of moles of water formed = 0.005
Use formula,
c = 4.18 kJ / kg °C, m = mass of mixed solution = 50 + 50 = 100 /1000 = 0.1 kg, = 3 °C
so, = - 4.18 x 0.1 x 3 = 1.254 kJ
0.005 moles 1.254 kJ
1 mole = - 2.5 x 102 kJ
Answered by Arvind Diwale | 19 Aug, 2014, 11:24: AM
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