5. IN HOW MANY WAYS 6 BOYS AND 6 GIRLS BE ARRANGED FOR A DINNER TABLE IF NO SIT TOGETHER (WITH EXPLANATION )

Asked by Satyam sinha | 13th Feb, 2014, 09:08: PM

Expert Answer:

Dear Student,
 
 
IN HOW MANY WAYS 6 BOYS AND 6 GIRLS BE ARRANGED FOR A DINNER TABLE IF NO SIT TOGETHER 
 
   (n −1)!n!
⇒(6 −1)!6!
⇒5.4.3.2.1.6.5.3.2.1.3⋅2⋅1⋅4⋅3⋅2⋅1 
 
 
 
 
Thanks and Regards
Topperas Team

Answered by  | 14th Feb, 2014, 11:52: AM

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