5. IN HOW MANY WAYS 6 BOYS AND 6 GIRLS BE ARRANGED FOR A DINNER TABLE IF NO SIT TOGETHER (WITH EXPLANATION )
Asked by Satyam sinha | 13th Feb, 2014, 09:08: PM
Expert Answer:
Dear Student,
IN HOW MANY WAYS 6 BOYS AND 6 GIRLS BE ARRANGED FOR A DINNER TABLE IF NO SIT TOGETHER
(n −1)!n!
⇒(6 −1)!6!
⇒5.4.3.2.1.6.5.3.2.1.3⋅2⋅1⋅4⋅3⋅2⋅1
Thanks and Regards
Topperas Team
Answered by | 14th Feb, 2014, 11:52: AM
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