4chairs and 3 tables cost RS.2100 and 5 chairs and 5 chairs and 2 tables cost RS.1750. find the

Asked by crama1965 | 24th May, 2010, 09:28: AM

Expert Answer:

Dear Student,

 

Let cost of each chair = Rs. x

and cost of each table = Rs. y

 

According to the statement, 4 chairs and 3 tables cost Rs. 2100

 

4 × (cost of one chair) + 3 × (cost of one table) = Rs. 2100

 

So, we get an equation

 

4x + 3y = 2100   ……...... (i)

 

Also, 5 chairs and 2 tables cost Rs.1750

 

So we get another equation

 

5x + 2y = 1750 ……….. (ii)

 

We will solve equations (i) and (ii) to get the answer

 

Let us solve the two equations using elimination method

 

2 × equation (i) gives

 

8x + 6y = 4200  ………………………… (A)

 

And 3 × equation (ii) gives

 

15x + 6y = 5250 ……………………….. (B)

 

Subtracting (A) from (B), we get

 

15x + 6y – 8x – 6y = 5250 – 4200

 

7x = 1050

 

 

 

So   x = 150

 

Substituting this value of x in equation (ii), we get

 

   5(150) + 2y = 1750

   750 + 2y = 1750

   2y = 1750 – 750

   2y = 1000

 

So   y = 500

 

Hence,   cost of each chair = Rs. 150

and        cost of each table = Rs. 500

 

 

Regards

Team

Topper Learning

Answered by  | 24th May, 2010, 12:50: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.