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CBSE Class 6 Answered

(4a+11b)+(2a–3b–(4a–2b)

Asked by subhashpandeydav | 08 Sep, 2019, 11:23: PM
Expert Answer
(4a+11b)+[2a–3b–(4a–2b)]
 
= 4a + 11b + (2a - 3b - 4a + 2b)

= (4a + 2a - 4a) + (11b - 3b + 2b)

= 2a + 10b
 
= 2(a + 5b)
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