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CBSE Class 8 Answered

(3y-1)/4+(2y+3)/3=(1-7y)/6 solve & verify
Asked by cvshagi | 29 Jun, 2018, 08:53: PM
answered-by-expert Expert Answer
begin mathsize 16px style fraction numerator left parenthesis 3 straight y space minus 1 right parenthesis over denominator 4 end fraction space plus space fraction numerator left parenthesis 2 straight y space plus space 3 right parenthesis over denominator 3 end fraction space equals space fraction numerator left parenthesis space 1 space minus 7 straight y right parenthesis over denominator 6 end fraction
rightwards double arrow fraction numerator 3 left parenthesis 3 straight y space minus 1 right parenthesis space plus space 4 left parenthesis 2 straight y space plus space 3 right parenthesis over denominator 12 end fraction space equals space fraction numerator begin display style left parenthesis 1 space minus 7 straight y right parenthesis end style over denominator begin display style 6 end style end fraction
rightwards double arrow fraction numerator 9 straight y space minus space 3 space plus space 8 straight y space plus space 12 over denominator 2 end fraction equals space left parenthesis 1 space minus 7 straight y right parenthesis
rightwards double arrow 17 straight y space plus space 9 space equals space 2 space minus space 14 straight y
rightwards double arrow 31 straight y space equals space minus 7
rightwards double arrow straight y space equals space fraction numerator negative 7 over denominator 31 end fraction end style
Answered by Yasmeen Khan | 02 Jul, 2018, 06:58: PM
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