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CBSE Class 10 Answered

3sin72
Asked by vinitha123 | 18 Feb, 2010, 11:08: AM
answered-by-expert Expert Answer

(3sin72)/(7cos18) = (3sin(90-18))/(7cos18) = (3(sin90cos18-cos90sin18))/(7cos18)

= (3cos18)/(7cos18) = 3/7

Regards,

Team,

TopperLearning.

Answered by | 18 Feb, 2010, 11:15: AM

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