3sin72/7cos18-4(cos square70 +cos square 20)/7(tan5 tan45 tan 85)

Asked by vinitha123 | 18th Feb, 2010, 11:12: AM

Expert Answer:

(3sin72)/(7cos18)-4(cos270 +cos220)/[7(tan5 tan45 tan 85)] =

We can write,

sin 72 = sin 90-18 = cos 18

Similarly, cos 70 = cos 90-20 = sin 20.

and tan 45 =1

and tan 5 = tan 90-85 = sin 90-85 / cos 90-85 = cos 85 / sin 85 = cot 85

Using these identities,

(3cos18)/(7cos18)-4(sin220 +cos220)/[7((cot85) (1) (tan 85))] =

3/7 - 4/7 = -1/7

Regards,

Team,

TopperLearning.

Answered by  | 18th Feb, 2010, 11:26: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.