3g of hydrogen react with 29g of oxygen to produce water according to the given equation 2H2+O2=2H2O a)identify the limiting reagent b)calculate the mass of h2o formed

Asked by Harini A | 8th Jul, 2013, 05:59: PM

Expert Answer:

2 H 2            + 02         ?  2 H2O
2 X 2.01          32 g            2 x (2.01 + 16 ) = 36 .032
4.03 g
 
3 g of H 2 needs  O2  =  32 
                               --------   X 3  = 23 .8 g
                                 4.032
 
S0, 29 g 0f Oxygen is in excess, and hydrogen is the limiting reagent.
 
H2O formed =  36.032  x 3    = 26.8 g
                   --------
                       4.032
 
 
O2 left unreacted = 29 - 23.8
                         =  5.2 g 

Answered by  | 18th Jul, 2013, 03:29: PM

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