CBSE Class 11-science Answered
3g of hydrogen react with 29g of oxygen to produce water according to the given equation 2H2+O2=2H2O
a)identify the limiting reagent
b)calculate the mass of h2o formed
Asked by Harini A | 08 Jul, 2013, 05:59: PM
Expert Answer
2 H 2 + 02 ? 2 H2O
2 X 2.01 32 g 2 x (2.01 + 16 ) = 36 .032
4.03 g
3 g of H 2 needs O2 = 32
-------- X 3 = 23 .8 g
4.032
S0, 29 g 0f Oxygen is in excess, and hydrogen is the limiting reagent.
H2O formed = 36.032 x 3 = 26.8 g
--------
4.032
O2 left unreacted = 29 - 23.8
= 5.2 g
Answered by | 18 Jul, 2013, 03:29: PM
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