3.6gram sample on combustion, gave 3.3 grams of CO2. The percentage of carbon in the sample is:

Asked by vikasg13.hardware | 11th Nov, 2017, 01:51: PM

Expert Answer:

% C= 12/44wt of CO2/wt* 100percent sign C equals 12 over 44 cross times fraction numerator space Wt space of space CO subscript 2 over denominator wt space of space sample end fraction cross times 100
space space space space equals fraction numerator 12 cross times 3.3 over denominator 44 cross times 3.6 end fraction cross times 100
space space space space equals space 25 percent sign
=12/44*3.3/3.6*100
=25

Answered by Varsha | 12th Nov, 2017, 10:28: PM