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ICSE Class 10 Answered

31.st ques
Asked by lovemaan5500 | 26 Dec, 2017, 11:26: AM
answered-by-expert Expert Answer
At PE= mgh = 0.2 kg x 10 x 1 = 2 joule
 
PE at A is zero because h =  0
 
PE at B = KE at A
 
KE at A is = 1/2 m v2    
 
Therefore TE=KE+PE=1/2 m v2  + 0 = 1/2 m v2    
 
Speed will be maximum at  A
Answered by Gajendra | 27 Dec, 2017, 04:48: PM

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