3.0 gms of H2 react with 29.0 gms of O2 to yield H20 A) Which is the limiting reactant? B) Calculate the maximum amount of water that can be formed. C) Calculate the amount of the reactant which remains unreacted.

Asked by shobhit_dc | 28th Jul, 2011, 03:23: AM

Expert Answer:

The balanced chemical equation for the reaction is

2H2 + O2  ? 2H2O

 
Moles of H2 = 3/2 = 1.5 mol
Moles of O2 =29/32 =0.906 mol
(A) Calculation of limiting reactant:-
  According to the above equation,
 2 mol of H2 require O2 =1 mol
Therefore, 1.5 mol of H2 require O2 = 1.5  /2 =0.75 mol
moles of O2 present =0.906 mol
Thus,  H2 is  the limiting  rectants.
(B) since H2 is the limiting reactant, so the amount of product formed depend on H2.
 2 mol of H2 produced H2O = 2 mol
1.5 mol of H2 produced H2O =1.5 mol
Threrfore maximum amount of H2O formed =1.5 mol
(C) O2 remains unreacted.
Number of moles of O2 added = 0.906 mol
Number of moles of O2 used up =0.75 mol
Number of moles of O2 remain unreacted =(0.906-0.75)=0.156 mol

Answered by  | 1st Aug, 2011, 03:40: PM

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