3)If 9th term of an AP is zero, prove that 29th term is double the 19th term.
Asked by | 24th Dec, 2009, 09:18: AM
Expert Answer:
an = a1 + (n-1)d
a9 = a1 + 8d = 0; a1 = -8d
a29 = a1 + 28d = -8s + 28d = 20d...(1)
a19 = a1 + 18d = 10d .....(2)
Hence a29 = 2a19
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Team,
TopperLearning.
Answered by | 24th Dec, 2009, 01:45: PM
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