# 3 equal resistors connected in series across a source of e.m.f together dissipitate 10 watt. if the same resistors are connected in parallel across the same e.m.f. then what will be the power dissipated ?

### Asked by anshu.swati | 18th Jul, 2014, 10:52: PM

Expert Answer:

For series, 10 = V^{2}/3R

For parallel, P = V^{2} /(R/3)

Solving, we get P = 90 W

### Answered by Sheetal Jalan | 20th Jul, 2014, 09:57: PM

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