3 capacitors of capacitances in the ratio 1:2:3 are connected in parallel .their effective capacitance in parallel is greater than that in series by 60/11 pF.calculate the individual capacitances.
Asked by Renu Mariam John | 1st Mar, 2013, 07:53: PM
Expert Answer:
(C+2C+3C)-6C/11 =60/11
C=1
so the indiv cap are:1pF,2pF and 3 pF
Answered by | 4th Mar, 2013, 06:05: PM
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