3 capacitors of capacitances in the ratio 1:2:3 are connected in parallel .their effective capacitance in parallel is greater than that in series by 60/11 pF.calculate the individual capacitances.

Asked by Renu Mariam John | 1st Mar, 2013, 07:53: PM

Expert Answer:

(C+2C+3C)-6C/11  =60/11
C=1
so the indiv cap are:1pF,2pF and 3 pF

Answered by  | 4th Mar, 2013, 06:05: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.