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ICSE Class 10 Answered

3(b)
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Asked by rdk_kulkarni | 07 Sep, 2020, 05:11: PM
answered-by-expert Expert Answer
To find the sum of 17 terms of an AP whose middle term is 40.
 
Let space straight a minus 8 straight d comma space straight a minus 7 straight d comma space straight a minus 6 straight d comma space straight a minus 5 straight d comma space straight a minus 4 straight d comma space straight a minus 3 straight d comma space straight a minus 2 straight d comma space straight a minus straight d comma space straight a comma space straight a plus straight d comma space straight a plus 2 straight d comma space space space space space space straight a plus 3 straight d comma space straight a plus 4 straight d comma space straight a plus 5 straight d comma space straight a plus 6 straight d comma space straight a plus 7 straight d comma space straight a plus 8 straight d space be space the space 17 space terms space in space AP. Middlemost space term space is space 40 So comma space straight a space equals space 40 Sum space of space all space terms space is equals space straight a minus 8 straight d space plus space straight a minus 7 straight d space plus space straight a minus 6 straight d space plus space straight a minus 5 straight d space plus space straight a minus 4 straight d space plus space straight a minus 3 straight d space plus space straight a minus 2 straight d space plus space straight a minus straight d space plus space straight a space plus space straight a plus straight d space plus space straight a plus 2 straight d space plus space space space space space straight a plus 3 straight d space plus space straight a plus 4 straight d space plus space straight a plus 5 straight d space plus space straight a plus 6 straight d space plus space straight a plus 7 straight d space plus space straight a plus 8 straight d equals 17 straight a equals 680 Sum space of space 17 space space terms space is space 680.
Answered by Renu Varma | 08 Sep, 2020, 10:50: AM

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ICSE 10 - Maths
please tell the final answer
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ICSE 10 - Maths
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ICSE 10 - Maths
3(b)
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Asked by rdk_kulkarni | 07 Sep, 2020, 05:11: PM
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ICSE 10 - Maths
determine which term of the AP 121,117,113 ....... is the first negative term
Asked by suneelmsc | 25 Apr, 2020, 09:34: PM
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ICSE 10 - Maths
Ap gp
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Asked by Subhamjha0834 | 13 May, 2019, 08:05: PM
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ICSE 10 - Maths
Divide 96 into four parts which are in AP and the ratio between product of their mean to product of their exterme is 15:7
Asked by m_shailander | 17 Feb, 2019, 03:08: PM
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ICSE 10 - Maths
If the sum of first m terms is n,and sum of first n terms is m,show that sum of first (m+n) terms is equal to -(m+n)  
Asked by gsitabhanu24 | 02 Feb, 2019, 09:57: AM
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ICSE 10 - Maths
Kanika was given her pocket money on 1st Jan 2016 .she puts ₹1 on day 1,₹ 2on day 2 and ₹ 3 on day 3 and continued on doing so till the end of the month ,from this money into her piggy bank. She also spent ₹204 of her pocket money and was found that at end of the month she still has ₹100 with her . How much money  was her pocket money for the month?
Asked by Anmolrishiket | 30 Jan, 2019, 12:27: PM
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ICSE 10 - Maths
If 8times of the 8th term of an AP is equal to 13 times of the 13th term, show that 21st term of an AP is zero.
Asked by Shreyas | 13 Jul, 2018, 08:01: AM
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ICSE 10 - Maths
The 3rd term of an GP is 4. Find the product of its first 5 terms.
Asked by bdroy_2014 | 08 Feb, 2018, 02:52: PM
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