3 and 4 are subscripts. Please explain the method.

Asked by Sayoni Maiti | 18th Apr, 2014, 07:20: PM

Expert Answer:

Given:

Two metallic oxides contain 27.6% and 30% oxygen respectively.

Ratio of metal and oxygen in first oxide, M3O4 = 72.4 : 27.6

Ratio of metal and oxygen in second oxide = 70 : 30

Let molecular mass of metal = M

Therefore, the percentage by weight of the metal in the oxide

Now,

Moles of metal in second oxide = 70 / 56 = 1.25

Moles of oxygen in second oxide = 30 / 16 = 1.875

Ration of moles of metal and oxygen = 1.25 : 1.875

   = 1 : 1.5

   = 2 : 3

Hence, formula of the second oxide = M2O3

Answered by  | 21st Apr, 2014, 12:33: PM

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