Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

3 and 4 are subscripts. Please explain the method.
Asked by Sayoni Maiti | 18 Apr, 2014, 07:20: PM
Expert Answer

Given:

Two metallic oxides contain 27.6% and 30% oxygen respectively.

Ratio of metal and oxygen in first oxide, M3O4 = 72.4 : 27.6

Ratio of metal and oxygen in second oxide = 70 : 30

Let molecular mass of metal = M

Therefore, the percentage by weight of the metal in the oxide

Now,

Moles of metal in second oxide = 70 / 56 = 1.25

Moles of oxygen in second oxide = 30 / 16 = 1.875

Ration of moles of metal and oxygen = 1.25 : 1.875

   = 1 : 1.5

   = 2 : 3

Hence, formula of the second oxide = M2O3

Answered by | 21 Apr, 2014, 12:33: PM
CBSE 11-science - Chemistry
Asked by mallikarjunasangi28 | 22 Jul, 2022, 07:57: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by kdimple765 | 17 Jul, 2022, 01:24: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by alfirozislam900 | 03 Jul, 2022, 01:24: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by alfirozislam900 | 03 Jul, 2022, 01:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by vibhutimandal70 | 26 Jun, 2022, 10:39: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by arpitsingh373667 | 24 Jun, 2022, 05:00: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by bhagwatkrutika6 | 22 Jun, 2022, 08:09: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by deathkiller9875 | 13 Jun, 2022, 08:14: PM
ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by sd8022567 | 10 Jun, 2022, 11:39: PM
ANSWERED BY EXPERT

Start your hassle free Education Franchisee and grow your business!

Know more
×