3(2x-1)^2+5(2x-1)-4=0

 

Asked by shruthinair5848.10sdatl | 1st Jul, 2020, 10:09: PM

Expert Answer:

Take 2x-1=y, the equation becomes
3y2+5y-4=0
This is in the form of a quadratic equation
We have a=3, b=5 and c=-4
Let's solve this using the quadratic formula method
y equals fraction numerator negative 5 plus-or-minus square root of left parenthesis 5 right parenthesis squared minus 4 left parenthesis 3 right parenthesis left parenthesis negative 4 right parenthesis end root over denominator 2 cross times 3 end fraction equals fraction numerator negative 5 plus-or-minus square root of 25 plus 48 end root over denominator 6 end fraction equals fraction numerator negative 5 plus-or-minus square root of 73 over denominator 6 end fraction
rightwards double arrow 2 x minus 1 equals fraction numerator negative 5 plus-or-minus square root of 73 over denominator 6 end fraction
rightwards double arrow 2 x equals fraction numerator negative 5 plus-or-minus square root of 73 over denominator 6 end fraction plus 1 equals fraction numerator 1 plus-or-minus square root of 73 over denominator 6 end fraction
rightwards double arrow x equals fraction numerator 1 plus-or-minus square root of 73 over denominator 12 end fraction

Answered by Renu Varma | 2nd Jul, 2020, 10:55: AM