2x+3y-5=0 , kx-6y-8=0

Asked by  | 27th May, 2009, 01:37: PM

Expert Answer:

2x+3y-5=0 , kx-6y-8=0

system of equations has a unique solution if a1/a2 b1/b2

So 2/k   3/-6  this gives k -4

So the system of equations has a unique solution for all real values of k except -4

 

Answered by  | 27th May, 2009, 03:09: PM

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