2x+3y-5=0 , kx-6y-8=0
Asked by | 27th May, 2009, 01:37: PM
Expert Answer:
2x+3y-5=0 , kx-6y-8=0
system of equations has a unique solution if a1/a2 
b1/b2
So 2/k 3/-6 this gives k -4
So the system of equations has a unique solution for all real values of k except -4
Answered by | 27th May, 2009, 03:09: PM
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