2positively charges separated by a distance 2m each other with a force of 0.36N . if the combine charge is 26(uc)micron, the charges are?

Asked by abhishek | 8th Jun, 2013, 04:21: PM

Expert Answer:

F = 0.36N
r = 2m
Using coloumbs law
F = kq1q2/r^2
0.36 = 9*10^9 *q1q2/4
q1*q2 = 0.16 * 10^-9 
 
Also, q1+ q2 = 26*10^-6
Hence, q1 (26*10^-6-q1) = 0.16*10^-9
 
Solving quadratic equation, q1 = 16uc and 10uC
Hence the 2 charges are 16uC and 10uC 

Answered by  | 9th Jun, 2013, 06:35: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.