Asked by lovemaan5500 | 27th Dec, 2017, 01:35: PM
2000 liter of water = 2000 kg of water
to raise 2000 kg of water to heigth 10m, required energy = m×g×h = 2000×9.8×10 Joules
workdone by the pump of 2 kW with 70% effeicency in t seconds = 2000×(100/70)×t joules
if this workdone is same as the required energy to raise 2000 kg of water to 10 m height, then time taken is given by
2000×(100/70)×t = 2000×9.8×10
t = (9.8×10×70)/100 = 9.8×7 = 68.6 s
Answered by | 27th Dec, 2017, 02:25: PM
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