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2.76g of silver carbonate (at mass of Ag =108) on being heated strongly yields a residue weighing ANS IS 2.16g.BUT HOW DID WE ARRIVE AT THIS ANS?PLS ELABORATE.
Asked by Anagha Plus two | 31 Aug, 2011, 09:01: PM
answered-by-expert Expert Answer
2Ag2CO3(s) ----> 4Ag(s) + 2CO2(g) + O2(g)
So, on strogly heating silver carbonate will produce silver.
No of moles of silver carbonate = 2.76 g/ 275.7 = 0.0100
No of moles of Ag = x g/ 108 =
275.7 g of Ag2CO3 produces 108 x 2 g of Ag.
2.76 g will produce = 108 x 2 x 2.76 / 275.7 = 2.16 g of silver.
Answered by | 08 Sep, 2011, 12:50: PM

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