ICSE Class 10 Answered

Reaction:

4NH_3(g)   +   5O_2(g)   →   4NO_(g)   +   6H₂O_(l)

  4vol.            5vol.            4vol.            6vol.

Volume of H₂O will be negligible as it is in the liquid form at room temperature.

(Note: Gay Lussac’s Law is not applicable to substances in liquid and solid states).

According to Gay Lussac’s Law,

4vols. of NH₃ require 5vols. Of oxygen

4 cm³ of NH₃ require 5 cm³ Of oxygen

Therefore, 224 cm³ of NH₃ require oxygen = 5/4 × 224 = 280 cm³

Hence, volume of oxygen required = 280 cm³

4vols. of NH₃ produce 4vols of NO

4 cm³ of NH₃ produce 4 cm³ of NO

Therefore 224 cm³ of NH₃ produce NO = 4/4 × 224 = 224 cm³

Hence, volume of NO produced = 224 cm³