22  ques

Asked by lovemaan5500 | 26th Nov, 2017, 12:43: PM

Expert Answer:

Heat energy required to melt the ice of mass 150 g = 150 × Latent Heat of Ice = 150 × 336  Joules
 
Heat energy lost by Steam of mass ms from 100°C vapour state to 100°C Liquid state = ms × Latent Heat of Steam = ms × 2260 Jouls
 
ms = (150 × 336 ) / 2260 = 22.3 g
 
Total mass of water = 150+30+22.3 = 202.3 g

Answered by  | 27th Nov, 2017, 03:00: PM