2.175 gm of non volatile solute is added in 39 gm of organic liquid.The lowering in the vapour pressure is 40 mm oh Hg. Calculate molar weight of solute>molecular weight of organic liquid is 78.Assuming solution to be dilute vapour pressure of pure liquid is 640mm of Hg.

Asked by Asif Ansari | 26th Jun, 2011, 12:33: AM

Expert Answer:

Mass of non volatile solute(WB) = 2.175 g
Mass of organic liquid (WA) =39 g
 Given lowering in the vapour pressure ( P0A-PA) = 40 mm of Hg
Vapour pressure of  pure liquid, P0A= 640 mm of Hg

molar mass of organic liquid = 78 g mol-1

For dilute solution,

(P0A-PA  /P0A  = (WB XMA) /(MB XWA)
   40/640 = (2.175 X78)/(MB X39)
MB =69.6 g mol-1
Therefore molar weight of solute =69.6 g mol-1

Answered by  | 27th Jun, 2011, 04:29: PM

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