CBSE Class 12-science Answered
2.15 numerical plz
Asked by lovemaan5500 | 04 Jan, 2020, 11:18: PM
Expert Answer
(i)Mole fraction of Na2S2O3 =Moles of Na2S2O3 / (Moles of Na2S2O3 +Moles of H2O)
Moles of Na2S2O3 =3
Moles of H2O=776/18
=43.11
Mole fraction of Na2S2O3 =3/3+43.11
=0.065
(ii) Molality of Na+ ion= (6/776)*1000
=7.732
Molality of S2O3_2 ions=(3/776)*1000
=3.865
Answered by Ravi | 05 Jan, 2020, 07:57: PM
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