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CBSE Class 12-science Answered

2.15 numerical plz
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Asked by lovemaan5500 | 04 Jan, 2020, 11:18: PM
answered-by-expert Expert Answer
(i)Mole fraction of Na2S2O3 =Moles of Na2S2O3 / (Moles of Na2S2O3 +Moles of H2O) 
 
                                 Moles of Na2S2O3 =3
                                 Moles of H2O=776/18
                                                   =43.11
 
Mole fraction of Na2S2O3 =3/3+43.11
                                    =0.065
 
(ii) Molality of Na+ ion= (6/776)*1000
                                =7.732
 Molality of S2O3_2 ions=(3/776)*1000
                                  =3.865
Answered by Ravi | 05 Jan, 2020, 07:57: PM
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