2 years later a father will be eight yeras more than three times the sons age. writa linear equations in two variables taking the fathers age as x and the sons age as y.

Asked by Ranjith Kumar Ranjith Kumar | 7th Mar, 2011, 10:06: PM

Expert Answer:

dear student,

father's  present age=x

son's  present age = y

 

Father's age two years later= x+2

son's age after two years= y+2

ATQ,

father's age after two years= 8+[3(son's age after two years)]

x+2=8+[3(y+2)]

 

Answered by  | 7th Mar, 2011, 07:20: PM

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