2 particles start from the same position in a circle of radius 20cm with speed 40pim/s and 36pim/s in the same direction. find the time when the particles will meet again

Asked by  | 12th Sep, 2012, 07:54: AM

Expert Answer:

Relative velocity of the fast particle wrt  the slow one=40pi -36pi =4pi m/s
The circumference distance covered with this relative vel:
4pi =2pi R/T    
     =2pi Rn  
T= time period of meeting
n= frequency
n=10 Hz
so after 1/10 sec they will again meet.

Answered by  | 12th Sep, 2012, 11:01: AM

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