2 particles start from the same position in a circle of radius 20cm with speed 40pim/s and 36pim/s in the same direction. find the time when the particles will meet again

Asked by  | 12th Sep, 2012, 07:54: AM

Expert Answer:

Relative velocity of the fast particle wrt  the slow one=40pi -36pi =4pi m/s
 
The circumference distance covered with this relative vel:
 
4pi =2pi R/T    
     =2pi Rn  
T= time period of meeting
R=radius
n= frequency
 
n=10 Hz
so after 1/10 sec they will again meet.

Answered by  | 12th Sep, 2012, 11:01: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.